- 48
- 54
- 36
- 64

Option 2 : 54

Since, 30A27B is divisible by 9.

3 + 0 + A + 2 + 7 + B = 12 + A + B will also be divisible by 9.

A + B = 6 or 15 ...1)

Since, 30A27B is divisible by 11.

(3 + A + 7) – (0 + 2 + B) = 8 + A – B will be either 0 or 11.

8 + A – B ≠ 0 [A and B are integers]

Hence, 8 + A – B = 11

⇒ A – B = 3 ...2)

From (1) and (2):

A + B ≠ 6 [A and B are integers]

A = 9 and B = 6

Required product = 9 × 6 = 54
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